黎曼假设的英文
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"黎曼假设"怎么读用"黎曼假设"造句
英文翻译手机版
- riemann hypothesis
- "黎"英文翻译 the Li nationality,one of th ...
- "曼"英文翻译 a surname
- "假设"英文翻译 suppose; assume; grant; pres ...
- "广义黎曼假设" 英文翻译 : extended riemann hypothesis
- "费因曼-盖尔-曼假设" 英文翻译 : feynman-gell mann hypothesis
- "黎曼" 英文翻译 : bernhard riemann; riemann roch group; riemann stieltjes integral; riemann zeta-function: theory and applications; riemannis zeta function; theorem of riemann roch type
- "假设" 英文翻译 : 1.(假使; 假定) suppose; assume; grant; presume; ansatz; guess; assumption; postulation; supposition 假设一种说法是正确的 assume a statement to be correct; 我们假设这消息是正确的。 let us suppose (that) the news is true.2.(科学研究上对客观事物的假定的说明; 假设) hypothesis 科学假设 a scientific hypothesis
- "黎曼波" 英文翻译 : riema wave; riemann wave
- "黎曼廖" 英文翻译 : riemannian manifold; riemannian space
- "黎曼面" 英文翻译 : riemann surface
- "涂黎曼" 英文翻译 : liman tu
- "原假设(零假设)" 英文翻译 : null hypothesis
- "般赫黎曼" 英文翻译 : bernhard riemann
- "闭黎曼面" 英文翻译 : closed riemann surface
- "非黎曼几何" 英文翻译 : non-riemannian geometry
- "假黎曼流形" 英文翻译 : pseudo-riemannian manifold
- "柯西-黎曼方程" 英文翻译 : cauchy-riemann equation
- "黎曼 罗里群" 英文翻译 : riemann roch group
- "黎曼ζ函" 英文翻译 : riemann zeta function
- "黎曼ζ函数" 英文翻译 : riemann zeta function
- "黎曼ξ函数" 英文翻译 : riemann zeta function; zeta function
- "黎曼不变量" 英文翻译 : riema 's invariant; riemann's invariant
- "黎曼猜想" 英文翻译 : riemann hypothesis
- "黎曼定积分" 英文翻译 : definite riemann integral
- "黎曼定理" 英文翻译 : riema 's theorem; riemann's theorem
例句与用法
- Wiles and / or they must also prove the riemann hypothisis ! !
威尔斯和或他们还必须证明黎曼假设! ! ! - Our goal in this paper will be to review jiang ' s achievements from his disproof of rh to his establishment of the new number theory
本文的目的是审视蒋(春暄)的成就,自他否定黎曼假设开始,到他创立的新数论。 - I will try myself furthermore to obtain a disproof of rh that is entirely information theoretic but for this i have still to wait to develop a broader mathematical theory of information
我自己将进一步努力获得完全信息理论性对黎曼假设的否定,但为此我还必须等待开发出更为广泛的信息数学理论。 - If any mathematician disagrees with this , then please answer this question : if it is acceptable for wiles to use rh , an unproved hypothesis , to prove flt , then can wiles now also to use flt in reverse to prove the unproved rh
如果任何数学家对此不同意,那么请回答这样一个问题如果能够接受怀尔斯使用黎曼假设,一个未经证明的假说假设,对费马大定理进行证明的话,那么由于同样理由,怀尔斯现在是否也可以用费马大定理反过来证明尚未证明的黎曼假设? - The present situation is very similar to the situation described in andersen ' s fairy tale “ the emperor ' s new cloths ” : wiles ( like those tailors in the fairy tale ) has used non - existing “ threads ” ( an unproved hypothesis rh ) to weave “ the most magnificent new cloths in the world for the emperor ” ( wiles ' s proof of flt ) , and misleads the ministers of the emperor to believe that only fools can not see and appreciate how magnificent are these new cloths for the emperor
目前的情况非常像安徒生的童话“皇帝的新衣”中的情景怀尔斯像童话中的裁缝一样采用“虚假的线”未经证实的“黎曼假设” “为皇帝编织出世界上最为华丽的新衣”怀尔斯200多页对费马大定理的“证明” ,并且误导皇帝及其大臣们相信只有傻子才看不见和不能欣赏“皇帝的新衣”多么华丽!
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